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An employer interviews 10 people for 6 management positions in a company, and 5 of the 10 people are men. If all 10 are qualified, in how many ways can the employer fill the management positions if exactly 3 are men?

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konrad509

[tex] \displaystyle
\binom{5}{3}\cdot\binom{5}{3}=\left(\dfrac{5!}{3!2!}\right)^2=\left(\dfrac{4\cdot5}{2}\right)^2=10^2=100 [/tex]

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