-2r + 3 [tex] \geq [/tex] 19
Subtract 3 from both sides
-2r [tex] \geq [/tex] 16
Divide by - 2 which will then flip the inequality
r [tex] \leq [/tex] - 8
Because it is an "or equal to" statement, the circle will be closed. And since it is "less than," R has to be anything to the left of - 8 on the number line.
Your answer is the third option.
