The electrical force acting on a charge q immersed in an electric field is equal to
[tex]F=qE[/tex]
where
q is the charge
E is the strength of the electric field
In our problem, the charge is q=2 C, and the force experienced by it is
F=60 N
so we can re-arrange the previous formula to find the intensity of the electric field at the point where the charge is located:
[tex]E= \frac{F}{q}= \frac{60 N}{2 C}=30 N/C [/tex]
