katelynn777 katelynn777
  • 18-08-2014
  • Mathematics
contestada

evalaute the following without using a calculator:
cos(13pi/6)

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kate200468
kate200468 kate200468
  • 18-08-2014
[tex]the\ cos\ function\ is\ periodic:\ \ \ the\ period=2 \pi\\\\cos(2 \pi + \alpha )=cos \alpha \\\\------------------------\\\\cos\bigg{(} \frac{\big{13 \pi }}{\big{6}}\bigg{)}=cos\bigg{(} 2 \pi +\frac{\big{ \pi }}{\big{6}}\bigg{)}=cos\bigg{(} \frac{\big{ \pi }}{\big{6}}\bigg{)}= \frac{\big{ \sqrt{3} }}{\big{2}} [/tex]
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Аноним Аноним
  • 18-08-2014
Answer is in the attachment below. Please open it up in a new window to see it in full.
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