Respuesta :
[tex]\bf \textit{equation of a circle}\\\\
(x- h)^2+(y- k)^2= r^2
\qquad
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad
radius=\stackrel{}{ \boxed{r}}\\\\
-------------------------------\\\\
(x+5)^2+(y+8)^2=16\implies (x+5)^2+(y+8)^2=\boxed{4}^2[/tex]
