payshencec21
payshencec21
19-03-2018
Mathematics
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WojtekR
WojtekR
19-03-2018
[tex]10x^2y^{-2}=\dfrac{10x^2}{y^2}\\\\\\ \dfrac{10\cdot(-1)^2}{(-2)^2}=\dfrac{10\cdot1}{4}=\dfrac{10}{4}=\dfrac{5}{2}=\boxed{2\dfrac{1}{2}}[/tex]
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