when we have the balanced equation for this reaction: AB3 ↔ A+3 + 3B- So we can get Ksp: when Ksp = [A+3][B-]^3 when [A+3] = 0.047 mol and from the balanced equation when 1 mol [A+3] → 3 mol [B-] 0.047 [A+3] → ?? [B-] = 3*0.047 = 0.141 so by substitution in Ksp formula: ∴Ksp = 0.047 * 0.141^3 = 1.32x10^-4