zjthomas4943 zjthomas4943
  • 19-03-2018
  • Mathematics
contestada

Find the zeros of the polynomial function.
f(x) = x^2 - 12x + 20
I THINK THE ANSWER IS A 2,10

a. 2, 10

b. - 4, -5

c. -2, -10

d. 4, 5

Respuesta :

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  • 25-03-2018
◆ QUADRATIC EQUATIONS ◆

[tex]given \: equation \: is \: , \\ \\ {x}^{2} - 12x + 20 = 0 \\ \\ using \: quadratic \: formula \: , \\ \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \: \: \: \: = \frac{ - ( - 12) + \sqrt{ { (- 12)}^{2} - 4(1)(20) } }{2(1)} \\ \\ x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \: \: \: \: = \frac{ - ( - 12) - \sqrt{ { (- 12)}^{2} - 4(1)(20) } }{2(1)} \\ \\ x = \frac{12 + 8}{2} \: \: \: \: \: or \: \: \: \: x = \frac{12 - 8}{2} \\ \\ x = 10 \: \: \: \: \: or \: \: \: \: \: x = 2 \: \: \: ans.[/tex]
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