deathmetal420
deathmetal420 deathmetal420
  • 19-01-2016
  • Mathematics
contestada

2b[tex] 2 b^{2} -26b+80=0??[/tex]

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pingwin09
pingwin09 pingwin09
  • 19-01-2016
Factor out it by 2.
2(b² - 13b + 40) = 0
b² - 13b + 40 =0
This equation can be solved using the quadratic formula. If you know what a quadratic formula is, then you can get the two values for b. For instance,
(b - 8)(b - 5) = 0

Separate the two "roots", you will get:
b - 8 = 0
b = 8
and
b - 5 = 0
b = 5

Therefore the two values of b are 8 and 5.
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