alearned123 alearned123

20-02-2018
Mathematics

contestada

8- 2 to the root of 4+8*2^3-(3+14-5)/12
I don't know if this makes sense but I need help with it.

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sqdancefan sqdancefan

20-02-2018

[tex] 8-2^{ \sqrt{4}} +8 \times 2^{3} -\frac{3+14-5}{12} [/tex]
[tex] = 8 -2^{2} +8 \times 8 -\frac{12}{12} [/tex]
[tex] = 8-4+64-1 = 67 [/tex]

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