darlanorton20p3x1jq darlanorton20p3x1jq
  • 18-02-2018
  • Mathematics
contestada

write the equation for the quadratic function that has the vertex at (1,3) and passes through the point (0,5)

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susanwiederspan
susanwiederspan susanwiederspan
  • 18-02-2018
For this quadratic, its vertex form [tex]f(x) = a(x-h)^2+k[/tex] is [tex]f(x) = a(x-1)^2+3[/tex].

To find the value of a, plug in (0,5) and solve. 

[tex]5 = a(0-1)^2+3 \\ a = 2[/tex]

The final equation in vertex form is [tex]f(x) = 2(x-1)^2+3[/tex].

In standard form [tex]f(x) = ax^2+bx+c[/tex], the function is [tex]f(x) = 2x^2-4x+5[/tex].
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