reedgallagher2014 reedgallagher2014

19-12-2017
Mathematics

contestada

How many real zeros does y = (x-8)^3 + 12 have?

Respuesta :

02-01-2018

To get the zeroes, we will equate the given equation with zero and solve for x as follows:
(x-8)^3 +12 = 0
(x-8)^3 = -12
x-8 = ∛-12
x - 8 ≈ -2.2894
x ≈ -2.2894 + 8
x ≈ 5.71

Based on the above, this equation has only one real zero

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