Officialxkaykay
Officialxkaykay
19-11-2015
Mathematics
contestada
8 (t+2)-3 (t-4)=6 (t-7) 8
Respuesta :
Аноним
Аноним
19-11-2015
∙•❁Okay we will now solve this Step-By-Step!❁•
∙•❁
Question:
8(t+2)−3(t−4)=6(t−7)(8)
∙•❁
Simplify both sides of the equation:
8(t+2)−3(t−4)
=
6(t−7)(8)
∙•❁
Now Simplify:
8(t+2)−3(t−4)
=
6(t−7)(8)
(8)(t)+(8)(2)+(−3)(t)+(−3)(−4)=48t+−336
Distribute
8t+16+−3t+12
=
48t+−336
(8t+−3t)+(16+12)=48t−336
Combine Like Terms
5t+28
=
48t−336
∙•❁
Subtract 48t from both sides.
5t+28−48t
=
48t−336−48t
−43t+28
=
−336
∙•❁
Subtract 28 from both sides:
−43t+28−28
=
−336−28
−43t
=
−364
∙•❁
Divide both sides by -43:
−43t/−43
=
−364/−43
∙•❁
Your final answer is:
364/43
∙•❁
I hope this helps!
❁•
Answer Link
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