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WILL GIVE BRAINLIEST-The number of pollinated flowers as a function of time in days can be represented by the function.

f(x)=(3)x/2



What is the average increase in the number of flowers pollinated per day between days 4 and 10?



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Respuesta :

backseatdog
Do: (f(10) - f(4))/(10 - 4)

f(10) = 3(10)/2 = 15
f(4) = 3(4)/2 = 6

Thus: (15-6)/(10-4) = 9/6 = 3/2

Rate of change is 3/2.

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