rainboworld5214 rainboworld5214
  • 18-10-2017
  • Chemistry
contestada

How many aluminum atoms are in 3.78 g of aluminum?

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ejelonubenedict
ejelonubenedict ejelonubenedict
  • 18-10-2017
molar mass of aluminum = 26.982 g/mol.
1 mol of Al = 26.9≈27g = 6.02×10²³ atoms [ avogadro's number]
meaning
1 g | Al = 6.02/27 × 10²³ atoms
so 3.78g | Al = 6.02×3.78]/27 ×10²³
= 0.8428 ×10²³ atoms
= 8.428 ×10²² atoms
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