Season4Ever
Season4Ever Season4Ever
  • 20-09-2017
  • Mathematics
contestada

show that f(x)=(x-2)^3+8 is one to one algebraically

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JayDilla
JayDilla JayDilla
  • 29-09-2017
What im thinking is this: F(a) = f(b) so have 2 equations written and plug a into one and b in the other

(a-2)^3+8   = a^3-8+8 = a^3

                                             =            a^3 = b^3 square root both side = a=b
 (b-2)^3+8  = b^3-8+8 = b^3


Thus it is 1:1.
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