Answer:
3.5 A counterclockwise
Explanation:
According to Kirchhoff's voltage law, the sum of the voltage drops and voltage gains around a loop is 0.
-I₁R₁ − I₂R₂ + ε₁ − I₂r₁ = 0
I₂ (r₁ + R₂) = ε₁ − I₁R₁
I₂ (0.5 Ω + 2.5 Ω) = 18 V − (4.75 A) (6.0 Ω)
I₂ = -3.5 A
The current through the top loop is 3.5 A. (The negative sign means it is in the opposite direction of what is drawn.)
