Harambe7035 Harambe7035
  • 20-08-2017
  • Mathematics
contestada

Which of these formulas is correctly rewritten from the original formula to solve for b? a = 3b - 2c?

Respuesta :

jameschow32osyhg7 jameschow32osyhg7
  • 20-08-2017
-3b=-a-2c
b=(a-2c)/-3
Answer Link
ApusApus ApusApus
  • 15-10-2019

Answer:

[tex]b=\frac{a+2c}{3}[/tex]

Step-by-step explanation:

We have been given an equation [tex]a=3b-2c[/tex]. We are supposed to solve the given equation for b.

First of all, we will switch sides of the given equation as:

[tex]3b-2c=a[/tex]

Let us add [tex]2c[/tex] on both sides:

[tex]3b-2c+2c=a+2c[/tex]

[tex]3b=a+2c[/tex]

Divide both sides by 3:

[tex]\frac{3b}{3}=\frac{a+2c}{3}[/tex]

[tex]b=\frac{a+2c}{3}[/tex]

Therefore, our required equation wold be [tex]b=\frac{a+2c}{3}[/tex].

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