Respuesta :

[tex]\bf g(x)=x-3\qquad h(x)=x^2+6 \\\\\\ (h\circ g)(1)\implies h[\ g(1)\ ]\impliedby \textit{now, let's find g(1) first} \\\\\\ g(1)=(1)-3\implies g(1)=\boxed{-2}\qquad thus \\\\\\ h[\ g(1)\ ]\implies h\left( \boxed{ -2}\right)\implies h(-2)=(-2)^2+6 \\\\\\ h(-2)=4+6\implies h(-2)=10\impliedby (h\circ g)(1)[/tex]

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