Respuesta :

Challenge accepted.

CE / 2 = 3JQ / 7
7(CE) = 2(3JQ)
7CE = 6JQ
 /6Q     /6Q
7CE
 /6Q = J

Answer is A. I ain't fully sure cuz I'm only in grade 9 lol
Banabanana
[tex] \frac{CE}{2}= \frac{3JQ}{7} \\ \\7CE= 2*3JQ \\ \\ 7CE= 6JQ \\ \\ J= \frac{7EC}{6Q} [/tex]