jvribs15
jvribs15
19-07-2017
Mathematics
contestada
x = t2 + 3, y = t2 - 2
eliminate the parameter
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jdoe0001
jdoe0001
19-07-2017
is just a matter of a system of equations and substitution
[tex]\bf \begin{cases} x=t^2+3\implies x-3=\boxed{t^2}\\ y=t^2-2\\ ------------\\ y=\boxed{x-3}-2\\ y=x-5 \end{cases}[/tex]
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sergibcnusa
sergibcnusa
19-07-2017
So, you have to get rid of t^2, get it in the first one:
t^2 = x-3,
Now you can go to the other equation: y = t^2 - 2 = (x-3)-2=x-5
It's a line indeed!
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