emmers111
emmers111 emmers111
  • 19-06-2017
  • Mathematics
contestada

ƒ(x) = –x2 – 4 for x = –3.

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Mehek
Mehek Mehek
  • 19-06-2017
I'm assuming it looks like this:

[tex]f(x) = -x^2 - 4[/tex]

So we start by plugging -3 for x

[tex]f(-3) = -(-3)^2 - 4[/tex]

Which becomes:

[tex]f(-3) = 3^2 - 4[/tex]

Now simplify

[tex]f(-3) = 9 - 4[/tex]

[tex]f(-3) = 5[/tex]
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