2825613876
2825613876 2825613876
  • 18-06-2017
  • Mathematics
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Find all solutions to the equation in the interval [0, 2π). (1 point) cos x = sin 2x

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  • 18-06-2017
cos x = sin 2x
cos x = 2 sin x cosx

2sin x cos - cos x = 0

cos x( 2 sin x - 1) = 0

cos x = 0 or sin x = 1/2

so required values of x are pi/6 , 5pi/6 ,   pi/2,  3pi/2.
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