Respuesta :

MissPhiladelphia

If you are looking for the possible combinations in that equation, you’ll have to use the combination formula which is n factorial over r factorial

 

So in the problem, there are 14 possible combinations

                                               5

 

It is computed by

14! = 14*13*12*11*10 divided by

5! = 5*4*3*2*1


So the answer is there are 2002 possible combinations