Interpreted: [tex]g(x) = \frac{x}{5} - 6[/tex]
Let [tex]y = g(x)[/tex]
[tex]y = \frac{x}{5} - 6[/tex]
[tex]x = \frac{y}{5} - 6[/tex] (Interchange the x and y-values)
[tex]\frac{y}{5} = x + 6[/tex] (Solve for y)
[tex]y = 5(x + 6)[/tex]
[tex]\therefore g^{-1}(x) = 5(x + 6)[/tex]
