Assuming each segment is 1 unit
[tex]c^2=a^2+b^2 \\ \\ c = \sqrt{a^2+b^2} [/tex]
F.
a = 4
b = 2
[tex]c= \sqrt{4^2+2^2}
\\\\c= \sqrt{16+4}
\\\\c= \sqrt{20} [/tex]
G.
a = 4
b = 1
[tex]c= \sqrt{4^2+1^2} \\\\c= \sqrt{16+1} \\\\c= \sqrt{17} [/tex]
H.
the length: 4units
I.
a = 3
b = 1
[tex]c= \sqrt{3^2+1^2} \\\\c= \sqrt{9+1} \\\\c= \sqrt{10} [/tex]
The correct answer is "G"
