Answer:
- AB = 3√3;
- P = 2√5 + 3√3 + √7.
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AB is the missing hypotenuse of the right triangle with shown legs.
Find AB using Pythagorean theorem:
- [tex]AB=\sqrt{AC^2+BC^2}[/tex]
- [tex]AB = \sqrt{(2\sqrt{5} )^2+(\sqrt{7})^2}=\sqrt{4*5+7}=\sqrt{27}=3\sqrt{3}[/tex]
Find the perimeter:
- P = AC + BC + AB
- P = 2√5 + 3√3 + √7
