B. (4.0 mol C2H6O) x (3/1) = 12 mol O2
C. Supposing all the C in the CO2 came from ethanol:
(88 g CO2) / (44.00964 g CO2/mol) x (3/2) x (31.99886 g O2/mol) = 96 g O2
D. (125 g C2H6O) / (46.06867 g C2H6O/ mol) x (2/1) x (44.00964 g CO2/mol) =
239 g CO2
(125 g C2H6O) / (46.06867 g C2H6O/ mol) x (3/1) x (18.01532 g H2O/mol) =
