Answer: [tex](x+8)(x-8)[/tex]
Step-by-step explanation:
The given polynomial : [tex]x^2-64[/tex]
Since both the terms are perfect square.
Rewrite the above equation in the form of difference of two squares:
[tex]x^2-(8)^2[/tex]
Using algebraic formula given below:-
[tex]a^2-b^2=(a+b)(a-b)[/tex]
[tex]\Rightarrow\ x^2-(8)^2=(x+8)(x-8)[/tex]
Hence, the factors of [tex]x^2-64=(x+8)(x-8)[/tex]
