Respuesta :
An athlete doing push-ups performs 650 kJ of work and loses 425 kJ of heat.The change in the internal energy of the athlete is -1075 J.
Given data:
- Work done, [tex]$W=650 \mathrm{~kJ}$[/tex]
- Heat losses, [tex]$Q=-425 \mathrm{~kJ}$[/tex]
The expression for the change in internal energy is,
[tex]$\Delta U=Q-W$[/tex]
Substitute the values,
[tex]$\begin{aligned}&\Delta U=-425-650 \\&\Delta U=-1075 \mathrm{~kJ}\end{aligned}$[/tex]
Therefore, the change in internal energy is [tex]$-1075 \mathrm{~kJ}$[/tex].
Hence, the option (B) is the correct option.
What is Internal Energy?
- Internal energy is defined as the entire amount of energy stored within a system. The internal energy of a system varies with the amount of work and heat applied to and generated by the system.
- If the system does work, it signifies that the system's internal energy has been reduced. Work done on the system, on the other hand, causes the system to accumulate energy.
- If, on the other side, the system loses heat, it is also losing energy. If the system gains heat, this implies that it also gains energy.
Learn more about Internal Energy https://brainly.com/question/11278589
#SPJ9
