Let's call the first consecutive even integer:
n
Then, the second consecutive even integer would be:
n
+
2
So, from the information in the problem we can now write and solve:
5
n
=
4
(
n
+
2
)
5
n
=
(
4
×
n
)
+
(
4
×
2
)
5
n
=
4
n
+
8
−
4
n
+
5
n
=
−
4
n
+
4
n
+
8
(
−
4
+
5
)
n
=
0
+
8
1
n
=
8
n
=
8
Therefore the first even integer is:
n
The second consecutive even integer is:
n
+
2
=
8
+
2
=
10
5
⋅
8
=
40
4
⋅
10
=
40
