Respuesta :
Reaction appears to get heavier as molar mass of Magnesium oxide is more than the molar mass of reactants.
Molar mass: It is defined as the sum of atomic mass of each atom in a molecule or compound. If its only an element, then molar mass is same as the atomic mass of that element.
Calculate the molar mass of Magnesium oxide.
- The formula of Magnesium oxide is [tex]MgO[/tex].
- The atomic mass of magnesium ([tex]Mg[/tex]) =24.305 g/mol
- The atomic mass of Oxygen ([tex]O[/tex]) = 16.000 g/mol
- Thus, the molar mass of [tex]MgO[/tex] is calculated as-
[tex]Molar\ mass\ of\ MgO = Atomic\ mass\ of\ Mg\ +Atomic\ mass\ of\ O\= = 24.305\ g/mol + 16.000\ g/mol\\ Molar\ mass\ of\ MgO = 40.305\ g/mol[/tex]
- Now, the formation of Magnesium oxide can be shown as-
[tex]2Mg + O_{2}[/tex]→[tex]2MgO[/tex]
- As the product ([tex]MgO[/tex]) has higher molar mass, that means the product formed would be heavier than reactants.
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