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Consider a gray and opaque surface at 0°c in an environment at 25°C. The surface has an emissivity of 0.8. if the radiation incident on the surface is 240 w/m^2 , The radiosity of this surface is?

Respuesta :

The radiosity of this surface is 299.95W/m².

Calculation :

Given, € 0.8

Ta=0°C 273K

For opaque body., T = 0

a+ p = 1

€ = a (Kirchoff's Law)

p = (1-E)

Radiosity = leaving energy from the surface

= px 240 +€σT4

= (1-E) × 240 +0.8 x 5.67 x 10-8 (2734)

= (1-0.8) × 240 +0.8 x 5.67 × 10-8 (2734)

= 299.95W/m²

So, now after doing the calculations we can say that the radiosity of the surface was 299.95W/m².

To know more about Radiosity please click here : https://brainly.com/question/14937321

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