contestada

What is the x-coordinate of the point that divides the directed line segment from j to k into a ratio of 2:5? x = (startfraction m over m n endfraction) (x 2 minus x 1) x 1 –4 –2 2 4

Respuesta :

MrRoyal

The x-coordinate of the point is -2

How to determine the coordinates of point C?

The points are given as:

J = (-6, -2)

K = (8, -9)

m : n = 2 : 5

The x-coordinates of the point is calculated as:

[tex]jk = \frac{m}{m+n} *(x_2 -x_1) +x_1[/tex]

So, we have:

[tex]jk = \frac{2}{2+5} *(8+6) -6[/tex]

This gives

[tex]jk = \frac{2}{7} *14 -6[/tex]

So, we have:

jk = 4 - 6

Evaluate

jk = -2

Hence, the x-coordinate of the point is -2

Read more about line segment ratio at:

https://brainly.com/question/15895161

#SPJ1

Ver imagen MrRoyal

Otras preguntas