The values of m and n from the given equation are 1/4 and -2
Polynomial functions
Given the polynomial function below
f(x) = mx^4+2x^3-3x^2+nx-4
If the zeros are 2 and -2, hence;
0 = 16m+16-12+2n-4
0 = 16m-16+12-2n-4
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16m+2n = 0
16m - 2n = 8
Subtract
2n+2n = -8
4n = -8
n = -2
Substitute for "m'
16m + 2(-2) = 0
16m = 4
m = 1/4
Hence the values of m and n from the given equation are 1/4 and -2
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