The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
What is the least number of buses needed to carry 710 passengers?
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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