Fineassjayla Fineassjayla
  • 20-05-2022
  • Physics
contestada

A grasshopper jumps at a 58.0 degree angle, and lands 3.28m away. What was its initial velocity ?

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pstnonsonjoku
pstnonsonjoku pstnonsonjoku
  • 24-05-2022

The range of a projectile as obtained from the calculation is 5.98 m/s.

What is the range?

The range is the distance that is covered by a projectile. The range of a projectile is given by the formula; R = u^2 sin 2θ/g

Where;

u = initial velocity

θ = angle turned

g = acceleration due to gravity

Now;

3.28 = u^2 sin 2(58)/9.8

u^2 = 3.28 * 9.8/ sin 2(58)

u = √3.28 * 9.8/ sin 2(58)

u =√32.144 /0.899

u = 5.98 m/s

Learn more about range of projectile:https://brainly.com/question/17016688

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