Answer:
[tex]p(even)= \frac{6}{11}[/tex]
Step-by-step explanation:
It's given in the question that;
The spinner is divided into 11 equal sections from 0 to 10.
You spin the spinner ONCE!
The total number of possibilities is six, and the total number of sample spaces is 11.
So the probability of getting an even number is; [tex]p(even)= \frac{6}{11}[/tex]
I hope this helps!
