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19-04-2022
Mathematics

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can anyone help me solve this problem? (b^2 j^2) ^3 (b^5 j^5 ) ^4

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19-04-2022

(b^2 j^2)^3 = b^2x3 j^2x3 = b^6 j^6
(b^5 j^5)^4 = b^5x4 j^5x4 = b^20 j^20
b^6 b^20 j^6 j^20 = b^26 j^26.

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