(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically scattered protons at 90°? (b) What is the energy of the inelastically scattered protons at 90° when the 'Li is left in its first excited state (0.477 MeV)?

Respuesta :

Answer:

First the charge is given 7.50×10^-6

Explanation:

so that we have

[tex]90 [/tex]

  • so that their is no cross sectional area of this angle

then the direction is one is left and other one is right so thats my hint

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