Respuesta :

Answer:[tex]2\sqrt{3}[/tex]

Step-by-step explanation:

Use pytha. theorem on leftmost triangle and get sqrt(13)

Use it again on the other triangle: 13+b^2=25

Aisin

First, we find the hypotenuse of the first triangle

(Use the pythagorean theorem) : [tex]3^{2} + 2^{2} = 9 + 4 = 13[/tex]

So, the length of the side = [tex]\sqrt{13}[/tex]

Now, we find x :

x(squared) = [tex]5^{2} -\sqrt{13} ^{2}[/tex] = 25 - 13 = 12

-> x = [tex]\sqrt{12}[/tex] = 2[tex]\sqrt{3}[/tex]