tuhhitsbethany9979 tuhhitsbethany9979

21-02-2022
Mathematics

contestada

If x-y=√3, x²-y²=√5 & a²-a√3+1=0, then find out the value of x+y

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devishri1977 devishri1977

21-02-2022

Answer:

√15/3

Step-by-step explanation:

x² - y² =√5

(x +y)*(x -y) = √5

(x +y) * √3 = √5

x+y = √5 / √3

x +y = √5*√3 / √3*√3

x +y = √15/3

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