fatimaanwer384 fatimaanwer384

19-01-2022
Chemistry

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2MG+O2 ...........2MGO
AR=MG=40 , O=16
calculate the mass of maganissium to form log of maganissium oxide

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pereiramelissa700 pereiramelissa700

19-01-2022

Mg + 1/2 O2 → MgO

1 mol = 24 g of Mg

X mol = 12 g of Mg

x = 0.5 moles of Mg

Mg :MgO = 1:1 (coefficient from equations using mole ratio)

So

0.5 moles of MgO

1 mol MgO = (24+16) g = 40 g

0.5 moles of MgO = 0.5 × 40

= 20 g of MgO produced

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