Answer:
[tex]\left(h,\:k\right)=\left(-\frac{3}{2},\:\frac{9}{4}\right),\:p=-\frac{1}{4}[/tex]
Step-by-step explanation:
[tex]x^2+3x+y=0[/tex]
[tex]4\left\bigg(-\frac{1}{4}\right)\left\bigg(y-\frac{9}{4}\right)=\left\bigg(x-\left\bigg(-\frac{3}{2}\right)\right)^2[/tex]
[tex]\bold{\mathrm{Therefore\:parabola\:properties\:are:}}[/tex]
[tex]\left(h,\:k\right)=\left(-\frac{3}{2},\:\frac{9}{4}\right),\:p=-\frac{1}{4}[/tex]
