Respuesta :

loneguy

[tex]\sqrt{x(x+1)} = 0\\\\\implies x (x+1) =0\\\\\implies x = 0 ~~ \text{or}~~ x = -1[/tex]

Answer:

x =  0, -1.

Step-by-step explanation:

√(x(x+1)) = 0

If we square both sides we get

x(x + 1) = 0

so  x= 0 or x = -1.

As the equation contains a square root we need to test for extraneous solutions:

x = 0,   √(0(0 +1) = 0 so x = 0 IS a solution.

x = -1,  √(-1(-1 +1) = 0  so x = -1 IS a solution .