Answer:
[tex]\frac{35}{52}=n[/tex]
Step-by-step explanation:
[tex]\frac{1}{3}(5n-1)=2(1-n)+\frac{1}{5}n[/tex]
[tex]\frac{5}{3}n-\frac{1}{3}=2-2n+\frac{1}{5}n[/tex]
[tex]\frac{5}{3}n-\frac{1}{3}=2-\frac{9}{5}n[/tex]
[tex]-\frac{1}{3}=2-\frac{52}{15}n[/tex] (-1/3 - 2 = -1/3 - 6/3 = -7/3)
[tex]-\frac{7}{3}=-\frac{52}{15}n[/tex] (multiply by reciprocal -15/52)
[tex]\frac{105}{156}=n[/tex]
[tex]\frac{35}{52}=n[/tex]
