kaihibbs kaihibbs
  • 20-11-2021
  • Mathematics
contestada

In ΔNOP, n = 880 cm, o = 350 cm and ∠P=22°. Find ∠N, to the nearest degree.

Respuesta :

Аноним Аноним
  • 20-11-2021

Answer:

Step-by-step explanation:

law of cosines to find p

p² = 880² + 350² - 2(880)(350)cos22

p = 570.749... cm

law of sines to find ∠N

sin22/570.749 = sinN/880

N = 35.280 or 144.719

As n is the longest side, N must be the largest angle

∠N = 145°

or we can use law of cosines to find N

880² = 350² + 570.75² - 2(350)(570.75)cosN

N = 144.719° or 215.281°

as an angle > 180° cannot occur in a triangle.

∠N = 145°

Answer Link

Otras preguntas

W hat is the largest binary number that can be expressed with 16 bits? what are the equivalent decimal and hexadecimal numbers
whats equivalent to 10/20
How many milligrams are equivalent to 150 dekagrams
Fructose and glucose are examples of
Which excerpt from a student essay maintains the most objective tone? A.Steinbeck's initial description of the stranger's wagon makes the character seem almost
How much did indiana residents donate to candidates in the 2008 presidential election cycle?
Can someone please help me. I'm behind and need to get caught up ☹️ 20 pts 1st one is working with triangles 2nd is working with quadrilaterals
_______ are produced in the light reactions and used in the Calvin cycle. A. NADP+ and ADP B. Sugar molecules C. Electrons and sugars D. NADP
Which would make more sense?
The pair of numbers whose sum is 8 and whose product is as large as possible is