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A piece of clay sits 0.20 meters from the center of a potter’s wheel. If the potter spins the wheel with a tangential speed of 2.0 meters per second, what is the magnitude of the centripetal acceleration of the piece of clay on the wheel?

Respuesta :

onyebuchinnaji

The centripetal acceleration of the piece of clay on the wheel at the given tangential speed is 20 m/s².

The given parameters;

  • radius of the potter's wheel, r = 0.2 m
  • linear speed, v = 2 m/s

The centripetal acceleration of the piece of clay on the wheel is calculated as follows;

[tex]a = \frac{v^2}{r} \\\\a = \frac{2^2}{0.2} \\\\a = 20 \ m/s^2[/tex]

Thus, the centripetal acceleration of the piece of clay on the wheel at the given tangential speed is 20 m/s².

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