Explanation:
First, we. need to convert the initial velocity of 85 km/hr into m/s:
[tex]85\:\dfrac{\text{km}}{\text{hr}}×\dfrac{1000\:\text{m}}{1\:\text{km}}×\dfrac{1\:\text{hr}}{3600\:\text{s}}=23.6\:\text{m/s}[/tex]
Next, we're going to use the equation below:
[tex]v^2 = v_0^2 + 2ax[/tex]
Since [tex]v=0\:\text{and}\:a = -1.3\:\text{m/s,}^2[/tex] we can solve for the distance x:
[tex]x = -\dfrac{v_0^2}{2a} = -\dfrac{(23.6\:\text{m/s})^2}{2(-1.3\:\text{m/s}^2)}[/tex]
[tex]\:\:\:\:\:\:\:=214.2\:\text{m}[/tex]
