A bag of M&M's contained 13 red, 15 yellow,
44 brown, 12 orange, and 9 green candies.
What percent of the M&M's were yellow?

Question

20-07-2021
Mathematics

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A bag of M&M's contained 13 red, 15 yellow,
44 brown, 12 orange, and 9 green candies.
What percent of the M&M's were yellow?

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sweg69 sweg69 · Answer 1 · 2021-07-20T16:20:10+02:00

sweg69 sweg69

20-07-2021

Answer:6.2%

Explanation:
1.start by adding all your different m&m colors together
2. Take the number you got from that and divide it by the number of yellow m&m’s

13+15+44+12+9 = 93
93/15 = 6.20%

Mark brainliest

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meredith28 meredith28 · Answer 2 · 2021-07-20T16:21:35+02:00

meredith28 meredith28

20-07-2021

Answer:

16%

Step-by-step explanation:

Use the percentage formula:

P × V1 = V2

Example:

EX: P × 30 = 1.5

P =

1.5

30

= 0.05 × 100 = 5%

Answer Link

A bag of M&M's contained 13 red, 15 yellow, 44 brown, 12 orange, and 9 green candies. What percent of the M&M's were yellow?

Respuesta :

Otras preguntas

A bag of M&M's contained 13 red, 15 yellow,
44 brown, 12 orange, and 9 green candies.
What percent of the M&M's were yellow?